One day, while doing some calculations involving the square root of 2, of which you’d most likely find boring, I discovered a little curiosity involving the square root of 2 by chance.

Multiply by 1, 2, 3 and so on but drop the decimals from the products. For instance, is equal to 8.485… but you don’t have a need for the decimal part. Thus, in this case is 8.

This has nothing to do with rounding up or down. You just have to drop the decimal part. In technical term, this is called the floor function , though you don’t have to worry about that.

The following shows the products of the square root of 2 multiplied by 1 through 25 without their decimal parts.

Write down each answer in a horizontal in a horizontal line as shown in Figure 1.

Fig. 1

Now, you will notice that some numbers are missing from the sequence. Write these missing numbers under the numbers in Figure 1. This is shown in Figure 2.

Fig. 2

Subtract the upper number from the lower number.

Note that the difference in these pairs is 2, 4, 6, 8, 10 and so on.

3 – 1 = 2

6 – 2 = 4

10 – 4 = 6

13 – 5 = 8

17 – 7 = 10

etc.

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Fascinating facts.

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Very interesting

I also have some things I discovered myself about square roots

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Nice to see someone smart and humble about Math. Thaniks mate. π

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Interesting post! I’m a starting blogger who wishes to write on interesting math stuff too, and these are the kinds of post I see myself writing.

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Very fascinating!

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Thanks.

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π

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Thanks for the like on my site. Peace be the Botendaddy.

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π

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Sqrt(2)*1 does not equal 1 it equals sqrt(2)!

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Please reread the instruction. I have never said that β2 is equal to 1. I stated that you multiply β2 by 1, 2, 3, etc. and drop the decimal. So in this case β2 Γ 1 = 1, instead of 1.414…

This is the floor function, i.e. β β2 Γ 1 β = 1

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Interesting. I wonder if this can be shown to be generally true. Can we define a function which would easily give us the sequence of “missing” numbers from the list?

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It can be proven through induction.

As for the function for the sequence of missing numbers:

a(n) = floor[n(2+β2)].

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Fascinating.

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Thanks!

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Very cool!

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π

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I don’t think you’d catch me doing any square roots… unless they are attached to a tree…. π

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Have you found any cube root? π

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Ha ha! I’m still trying to find X π

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