One day, while doing some calculations involving the square root of 2, of which you’d most likely find boring, I discovered a little curiosity involving the square root of 2 by chance.

Multiply by 1, 2, 3 and so on but drop the decimals from the products. For instance, is equal to 8.485… but you don’t have a need for the decimal part. Thus, in this case is 8.

This has nothing to do with rounding up or down. You just have to drop the decimal part. In technical term, this is called the floor function , though you don’t have to worry about that.

The following shows the products of the square root of 2 multiplied by 1 through 25 without their decimal parts.

Write down each answer in a horizontal in a horizontal line as shown in Figure 1.

Fig. 1

Now, you will notice that some numbers are missing from the sequence. Write these missing numbers under the numbers in Figure 1. This is shown in Figure 2.

Fig. 2

Subtract the upper number from the lower number.

Note that the difference in these pairs is 2, 4, 6, 8, 10 and so on.

3 – 1 = 2

6 – 2 = 4

10 – 4 = 6

13 – 5 = 8

17 – 7 = 10

etc.

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## About Edmark M. Law

My name Edmark M. Law. I work as a freelance writer, mainly writing about science and mathematics. I am an ardent hobbyist. I like to read, solve puzzles, play chess, make origami and play basketball. In addition, I dabble in magic, particularly card magic and other sleight-of-hand type magic. I live in Hong Kong.
I blog at

learnfunfacts.com. You can find me on Twitter

@EdmarkMLaw and

Facebook. My email is learnfunfacts@gmail.com

I don’t think you’d catch me doing any square roots… unless they are attached to a tree…. π

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Have you found any cube root? π

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Ha ha! I’m still trying to find X π

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Very cool!

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π

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Fascinating.

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Thanks!

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Interesting. I wonder if this can be shown to be generally true. Can we define a function which would easily give us the sequence of “missing” numbers from the list?

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It can be proven through induction.

As for the function for the sequence of missing numbers:

a(n) = floor[n(2+β2)].

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Sqrt(2)*1 does not equal 1 it equals sqrt(2)!

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Please reread the instruction. I have never said that β2 is equal to 1. I stated that you multiply β2 by 1, 2, 3, etc. and drop the decimal. So in this case β2 Γ 1 = 1, instead of 1.414…

This is the floor function, i.e. β β2 Γ 1 β = 1

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Thanks for the like on my site. Peace be the Botendaddy.

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π

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Very fascinating!

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Thanks.

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π

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Interesting post! I’m a starting blogger who wishes to write on interesting math stuff too, and these are the kinds of post I see myself writing.

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Nice to see someone smart and humble about Math. Thaniks mate. π

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